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Calculate the reduction potential for th...

Calculate the reduction potential for the following half cell reaction at 298 K.
`Ag^(+)(aq)+e^(-)toAg(s)`
`"Given that" [Ag^(+)]=0.1 M and E^(@)=+0.80 V`

A

0.741 V

B

0.80 V

C

`-0.80`V

D

`-0.741`V

Text Solution

Verified by Experts

The correct Answer is:
A
`Ag^(+) + e^(-) to Ag`
`E_"cell"=E_"cell"^@-0.0591/1 "log" 1/([Ag^+])`
`E_"cell"=0.80-0.0591/1 "log" 1/0.1` =0.80-0.591=0.741 V
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