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Calculate DeltaG^(@) for the reaction : ...

Calculate `DeltaG^(@)` for the reaction : `Cu^(2+)(aq) +Fe(s) hArr Fe^(2+)(aq) +Cu(s)`. Given that `E^(@)Cu^(2+)//Cu = 0.34 V`,
`E_(Fe^(+2)//Fe)^(@) =- 0.44 V`

A

11.44 kJ

B

180.8 kJ

C

150.5 kJ

D

28.5 kJ

Text Solution

Verified by Experts

The correct Answer is:
C
`E_"cell"^@=E_(Cu^(2+)//Cu)^@-E_(Fe^(2+)//Fe)^@` = 0.34V-(0.44) V =0.78 V
`DeltaG^@= - nFE_"cell"^@` = -2 x 96500 x 0.78 = 150540 J or 150.5 kJ
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