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What would be the equivalent conductivit...

What would be the equivalent conductivity of a cell in which 0.5 salt solution offers a resistance of 40 ohm whose electrodes are 2 cm apart and 5 `cm^2` in area?

A

`10 "ohm"^(-1) "cm"^(2) "eq"^(-1)`

B

`20 "ohm"^(-1) "cm"^(2) "eq"^(-1)`

C

`30 "ohm"^(-1) "cm"^(2) "eq"^(-1)`

D

`25 "ohm"^(-1) "cm"^(2) "eq"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`K=1/Rxx1/A=1/40xx2/5`
`Lambda_"eq"=Kxx1000/N=1/40xx2/5xx1000/0.5= 20 ohm^(-1) cm^2 eq^(-1)`
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NCERT FINGERTIPS-ELECTROCHEMISTRY-Conductance Of Electrolytic Solutions
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