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The equivalent conductivity of N/10 solu...

The equivalent conductivity of N/10 solution of acitic acid at `25^(@)C` is `14.3 ohm^(-1) cm^(2) eq^(-1)`. Calculate the degree of dissociation of `CH_(3)COOH` if `Lambda_(oo CH_(3)COOH)` is 390.71.

A

`3.66%`

B

`3.9%`

C

`2.12%`

D

`0.008%`

Text Solution

Verified by Experts

The correct Answer is:
A

`Lambda_(m " " CH_3COOH)^@`=390.71 `"ohm"^(-1) "cm"^2 "equiv"^(-1)`
`Lambda_(CH_3COOH)=143 "ohm"^(-1) "cm"^2 "equiv"^(-1)`
Degree of dissociation (`alpha`) =`Lambda_m^c/Lambda_m^(oo)=14.3/390.71`=0.0366 i.e. 3.66%
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