How many moles of Pr may be deposited on the cathode when 0.80F of electricity is passed through 1.0M solution of `Pt^(4+)`?

Options

A. 0.1 mol
B. 0.2 mol
C. 0.4 mol
D. 0.6 mol

Answer

B

Explanation

`Pt^(4+) + 4e^(-) to Pt`
4 moles of electricity or 4 F of electricity is required to deposit 1 mole of Pt.
0.80 F of electricity will deposit `1/4xx0.80` =0.20 mol