An acidic solution of `Cu^(2+)` ions containing 0.4 g of `Cu^(2+)` ions is electrolysed until all the copper is deposited. Calculate the valume of oxygen evolved at N.T.P.

Options

A. 141 cc
B. 31.75 cc
C. 64 cc
D. 32 cc

Answer

A

Explanation

`{:(H_2O to 2H^(+) + 1/2O_2 + 2e^(-) ,"(Oxidation)"),(Cu^(2+)+2e^(-) to Cu, "(Reduction)"),( Cu^(2+)+H_2O to Cu+2H^(+)+ 1/2O_2,):}`
`63.5/2`=31.75 g of `Cu^(2+)-=1/2xx11200` cc of `O_2`
31.75 g of `Cu^(2+)` evolve 11200 cc of `O_2` at NTP
0.4 g of `Cu^(2+)` will evolve `11200/31.75xx0.4` = 141 cc of `O_2`