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For this reaction N(2(g))+3H(2(g))t...

For this reaction
`N_(2(g))+3H_(2(g))to2NH_(3(g))`
The relation between `(d(NH_(3)))/(dt)` and `-(d(H_(2)))/(dt)` is :-

A

`-(1)/(3) (d[H_(2)])/(dt) = + (1)/(2) (d[NH_(3)])/(dt)`

B

`-(1)/(2) (d[H_(2)])/(dt) = + (1)/(3) (d[NH_(3)])/(dt)`

C

`+(1)/(2) (d[H_(2)])/(dt) = - (1)/(3) (d[NH_(3)])/(dt)`

D

`+(1)/(3) (d[H_(2)])/(dt) = - (1)/(2) (d[NH_(3)])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
A
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