The rate of formation of a dimer in a second order dimerisation reaction is `9.1 xx 10^(-6) mol L^(-1)s^(1)` at 0.01 mol `L^(-1)` monomer concentration. Calculate the rate consant for the reaction.

Options

A. `9.1 xx 10^(-2) L mol^(-1) s^(-1)`
B. `9.1 xx 10^(-6) mol^(-1) s^(-1)`
C. `3 xx 10^(-4) L mol^(-1) s^(-1)`
D. `27.3 xx 10^(-2) L mol^(-1) s^(-1)`

Answer

A

Explanation

`2A to A_(2)`
Rate of formation of dimer = `k [A]^(2)`
`k = ("Rate of formation of dimer")/([A]^(2))`
`k = (9.1 xx 10^(-6) mol L^(-1) s^(-1))/((0.01 mol L^(-1))^(2)) = 9.1 xx 10^(-2) L mol^(-1) S^(-1)`