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Rate constant of two reactions are given...

Rate constant of two reactions are given below. Identifying their order of reaction
`k = 5.3 xx 10^(-2) L mol^(-1) s^(-1)`
`k = 3.8 xx 10^(-4) s^(-1)`

A

(i) second order, (ii) first order

B

(i) first order, second order

C

(i) zero order, (ii) first order

D

(i) second order, (ii) zero order

Text Solution

Verified by Experts

The correct Answer is:
A

For second order, rate constant
`= (mol L^(-1))/(s) x (1)/((mol L^(-1))^(2)) = mol^(-1) L s^(-1)`
For first order, rate constant`= (mol L^(-1))/(s) xx (1)/(mol L^(-1)) = s^(-1)`
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