Calculate the half life of the reaction `ArarrB`, when the initial concentration of A is `0.01 "mol" L^(-1)` and initial rate is `0.00352 "mol" L^(-1)"min"^(-1)`. The reaction is of the first order

Options

A. 19.69 min
B. 1.969 min
C. 7.75 min
D. 77.5 min

Answer

B

Explanation

`(dx)/(dt) = k [X]` (for a first order reaction)
`0.00352 = k xx 0.01 implies k = 0.352`
`t_(1//2) = (0.693)/(k) = (0.693)/(0.352) = 1.969` min