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A hypothetical reaction A(2) + B(2) rarr...

A hypothetical reaction `A_(2) + B_(2) rarr 2AB` follows the mechanism as given below:
`A_(2) hArr A+A ("fast")`
`A+B_(2) rarr AB+B` (slow)
`A+B rarr AB` (fast)
The order of the overall reaction is

A

2

B

1

C

43892

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
As rate depends upon the slow step,
Rate `= k [A] [B_(2)]`
for the equilibrium, `A_(2) hArr 2A, K_(C ) = ([A]^(2))/([A_(2)])`
or `[A] = sqrt(k_(C )[A_(2)])`
`:.` Rate `= k K_(c )^(1//2) [A_(2)]^(1//2) [B_(2)] = k' [a_(2)]^(1//2) [B_(2)]`
Hence order `= (1)/(2) + 1 = (3)/(2)`
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