Home
Class 12
CHEMISTRY
For Freundlich adsorption isotherm, (x)/...

For Freundlich adsorption isotherm, `(x)/(m)=kp^1//n` , the value of n is

A

always greater than one

B

always smaller

C

always equal to one

D

greater than one at low temperature and smaller than one at high temperature.

Text Solution

Verified by Experts

The correct Answer is:
A

n is always greather than one.
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    NCERT FINGERTIPS|Exercise Catalysis|14 Videos
  • SURFACE CHEMISTRY

    NCERT FINGERTIPS|Exercise Colloids And Classification Of Colloids|45 Videos
  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos
  • THE D- AND F- BLOCK ELEMENTS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

Freundlich adsorption isotherm is

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) In the mathematical relation of Freundlich adsorption isotherm ,the value of (1/n) is 0 le (1)/(n) le 1 . (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) Freundlich adsorption isotherm is valid for chemisorption . (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) When "log"((x)/(m)) is plotted against log P, we get a straight line with slope (1/n). (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) The degree of adsorption (x/m) at low pressure will be : (x)/(m) =a (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) When ((x)/(m)) is plotted against (1)/(p) ,we get a straight line slope (1/a) and intercept (b/a). (a) True (b) False

NCERT FINGERTIPS-SURFACE CHEMISTRY-Assertion And Reason
  1. For Freundlich adsorption isotherm, (x)/(m)=kp^1//n , the value of n i...

    Text Solution

    |

  2. Assertion : Solids in finely divided state act as good adsorbents. ...

    Text Solution

    |

  3. Assertion : Silica gel is used to dry air. Reason : Silica gel absor...

    Text Solution

    |

  4. Assertion : In physical adsorption , enthalpy of adsorption in very lo...

    Text Solution

    |

  5. Assertion : Physical adsorption increases with increase in temperature...

    Text Solution

    |

  6. Assertion : Physisorption of a gas adsorbed at low temperature may cha...

    Text Solution

    |

  7. Assertion : Hydrolysis of ester is an example of auto-catalytic reacti...

    Text Solution

    |

  8. Assertion : Zeolites are good shape-selective catalyst. Reason : Ze...

    Text Solution

    |

  9. Assertion : Amylase in the presence of sodium choride i.e., Na^(+) ion...

    Text Solution

    |

  10. Assertion : Lyophilic sols are reversible sols. Reason : Lyophilic...

    Text Solution

    |

  11. Assertion : Colloidal sol scatters ight while true solution does not. ...

    Text Solution

    |

  12. Assertion : The values of colligative properties are of smaller order ...

    Text Solution

    |

  13. Assertion : When KI solution is added to AgNO(3) solution, negatively ...

    Text Solution

    |

  14. Assertion : In the coagulation of a negative sol the flocculating powe...

    Text Solution

    |

  15. Assertion : Lyophilic colloids have a unique property of protecting ly...

    Text Solution

    |

  16. Assertion : For stabilisation of an emulsion a third component called ...

    Text Solution

    |