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A brown ring is formed in the ring test ...

A brown ring is formed in the ring test for `NO_(3)^(-)` ion. It is due to the formation of

A

`[Fe(H_(2)O)_(5)(NO)]^(2+)`

B

`FeSO_(4)cdot NO_(2)`

C

`[Fe(H_(2)O)_(4)(NO)_(2)]^(2+)`

D

`FeSO_(4)cdot HNO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`NO_(3)^(-)+3Fe^(2+)+4H^(+)rarrNO+3Fe^(3+)+2H_(2)O`
`[Fe(H_(2)O)_(6)]^(2+)+NOrarrunderset("(Brown)")([Fe(H_(2)O)_(5)(NO)])^(2+)+H_(2)O`
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