What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid ?

Options

A. `Cr^(3+) and Cr_2O_7^(2-)` are formed
B. `Cr_2O_7^(2-) and H_2O` are formed
C. `CrO_4^(2-)` is reduced to +3 state of Cr
D. `CrO_4^(2-)` is oxidised to +7 state of Cr.

Answer

B

Explanation

Dilute nitruc acid converts chromate into dichromate and `H_2O`.
`2K_2CrO_4+2HNO_3 to K_2Cr_2O_7 + 2KNO_3+H_2O`
or, `underset("yellow")(2CrO_4^(2-))overset(H^(+))hArrunderset("orange")(Cr_2O_7^(2-))+H_2O`