When acidified `K_(2)Cr_(2)O_(7)` solution is added to `Sn^(2+)` salts then `Sn^(2+)` changes to

Options

A. Sn
B. `Sn^(3+)`
C. `Sn^(4+)`
D. `Sn^(+)`

Answer

C

Explanation

`Cr_2O_7^(2-)+14H^(+)+3Sn^(2+)to2Cr^(3+)+3Sn^(4+)+7H_2O`