A coordination compound `CrCI_(3).4H_(2)O` precipitates `AgCI` when treated with `AgNO_(3)` The molar conductance of its solution corresponds to a total of two ions Write the structural formula of the compound and name it .

Options

A. `[Cr(H_(2)O)_(4) Cl_(3)]`
B. `[Cr(H_(2)O)_(3)Cl_(3)]H_(2)O`
C. `[Cr(H_(2)O)_(4)Cl_(2)]Cl`
D. `[Cr(H_(2)O)_(4)Cl]Cl_(2)`

Answer

C

Explanation

It gives precipitate with `AgNO_(3)` it means it gives `Cl^(-)` ions in the solution . Since conductivity corresponds to two ions , it shows one `Cl^(-)` is outside the coordination sphere . The structure will be
`[Cr(H_(2)O)_(4) Cl_(2)]Cl to [Cr(H_(2)O)_(4)Cl_(2)]^(+) + Cl^(-)`
`AgNO_(3) + Cl^(-) to underset("white ppt.")(AgCl) + NO_(3)^(-)`