Correct formula of tetraamminechloronitroplatinum (IV) sulphate can be written as

Options

A. `[Pt(NH_(3))_(4) (ONO)Cl]SO_(4)`
B. `[Pt(NH_(3))_(4) Cl_(2)NO_(2)]_(2)SO_(4)`
C. `[Pt(NH_(3))_(4) (NO_(2))Cl]SO_(4)`
D. `[PtCl(ONO)NH_(3)(SO_(4))]`

Answer

To derive the correct formula for tetraamminechloronitroplatinum(IV) sulfate, we can follow these steps:

### Step 1: Identify the components of the complex
The name "tetraamminechloronitroplatinum(IV) sulfate" indicates that the complex consists of:
- Tetraammine: 4 ammonia (NH₃) ligands
- Chloro: 1 chloride (Cl) ligand
- Nitro: 1 nitro (NO₂) ligand
- Platinum(IV): Platinum is in the +4 oxidation state
- Sulfate: The sulfate ion (SO₄) is present as a counter ion.

### Step 2: Determine the oxidation state of the platinum
Platinum is in the +4 oxidation state as indicated by the (IV) in the name. Therefore, we need to account for the charges contributed by the ligands.

### Step 3: Calculate the total charge from the ligands
- Each ammonia (NH₃) is a neutral ligand, contributing 0 charge.
- The chloride (Cl) contributes -1 charge.
- The nitro (NO₂) ligand is also neutral in this context.

Thus, the total charge from the ligands is:
\[ 0 \, (\text{from } NH_3) + (-1) \, (\text{from } Cl) + 0 \, (\text{from } NO_2) = -1 \]

### Step 4: Determine the overall charge of the complex
The overall charge of the complex cation can be calculated as follows:
\[ \text{Charge of platinum} (+4) + \text{Charge from ligands} (-1) = +4 - 1 = +3 \]

### Step 5: Write the formula of the complex cation
The complex cation is therefore:
\[ [Pt(NH_3)_4ClNO_2]^{3+} \]

### Step 6: Combine with the sulfate anion
Sulfate (SO₄) has a charge of -2. To balance the charges, we need two sulfate ions for every one complex cation:
\[ [Pt(NH_3)_4ClNO_2]^{3+} + 2SO_4^{2-} \]

### Step 7: Write the final formula
The final formula of the compound, combining the complex cation and the sulfate anions, is:
\[ [Pt(NH_3)_4ClNO_2]_{2}(SO_4)_{3} \]

### Final Answer
The correct formula of tetraamminechloronitroplatinum(IV) sulfate can be written as:
\[ [Pt(NH_3)_4ClNO_2]_{2}(SO_4)_{3} \]

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