When excess of ammonia is added to `CuSO_4` solution, the deep blue coloured complex is formed. Complex is

Options

A. tetrahedral and paramagnetic
B. tetrahedral and diamagnetic
C. square planar and diamagnetic
D. square planar and paramagnetic .

Answer

D

Explanation

`Cu^(2+) + 2OH^(-) to Cu(OH)_(2)`
`Cu(OH)_(2) + 4NH_(3) to underset("deep blue")([Cu(NH_(3))_(4))]^(2+) + 2 OH^(-)`
In `[Cu(NH_(3))_(4)]^(2+)` oxidation state of Cu = + 2

Hybridisation is `dsp^(2)` hence geometry is square planar and paramagnetic due to presence of one unpaired electron .