`0.02` mole of `[Co(NH_(3))_(5)Br]Cl_(2)` and 0.02 mole of `[Co(NH_(3))_(5) Cl] SO_(4)` are present in 200 cc of a solution X . The number of moles of the precipitates Y and Z that are formed when the solution X is treated with excess silver nitrate and excess barium chloride are respectively

Options

A. 0.02 , 0.02
B. 0.01 , 0.02
C. 0.02 , 0.04
D. 0.04 , 0.02

Answer

D

Explanation

`[Counderset(0.02 "mole") underset(1"mole") ((NH_(3))_(5))Br]Cl_(2) + 2 underset(2 "moles")(AgNO_(3)) to [Co(NH_(3))_(5)underset(1 "mole")(Br)](NO_(3))_(2) + 2 Agunderset(2 "moles")(Cl)_((ppt)) (Y)`
`0.02 xx 2 = 0.04 ` mole
`[Co(NH_(3))_(5)underset(1 "mole")(Cl)]SO_(4) + underset(0.02 "moles")(BaCl_(2)) to [Co(NH_(3))_(5)underset(1 "mole")(Cl)] Cl_(2) + BaSO_(4)_("(ppt.)") underset(0.02 "moles")((Z))`