Identify the products (A) and (B) in the reactions.
`RX+AgCNtoul((A))+AgX`
`RX+KCNtoul((B))+KX`

Options

A. (A)-RCN, (B)- RCN
B. (A)-RCN, (B)-RNC
C. (A)-RNC, (B)-RCN
D. (A)-RNC, (B)-RNC

Explanation

To identify the products (A) and (B) in the given reactions, we need to analyze the reactions step by step.

### Step 1: Analyze the first reaction
The first reaction is:
\[ \text{RX} + \text{AgCN} \rightarrow \text{A} + \text{AgX} \]

- Here, RX represents a haloalkane where R is an alkyl group and X is a halogen (like Cl, Br, or I).
- AgCN (silver cyanide) is a covalent compound. In this reaction, the cyanide ion (CN⁻) will react with the haloalkane.
- Due to the nature of AgCN being covalent, the nitrogen atom in the cyanide ion is more available for bonding.

**Product A:**
- The reaction leads to the formation of isocyanide (or carbylamine), which has the structure R-N≡C. Thus, product A is:
\[ \text{A} = \text{RNC} \]

### Step 2: Analyze the second reaction
The second reaction is:
\[ \text{RX} + \text{KCN} \rightarrow \text{B} + \text{KX} \]

- Here, KCN (potassium cyanide) is an ionic compound. In this case, the cyanide ion (CN⁻) will also react with the haloalkane.
- Since KCN is ionic, the carbon atom in the cyanide ion is more likely to participate in the nucleophilic attack on the haloalkane.

**Product B:**
- The reaction leads to the formation of cyanide (nitrile), which has the structure R-C≡N. Thus, product B is:
\[ \text{B} = \text{RCN} \]

### Final Products
- Therefore, the products of the reactions are:
- **Product A:** RNC (isocyanide)
- **Product B:** RCN (nitrile)

### Summary of Products:
- **A = RNC (isocyanide)**
- **B = RCN (nitrile)**

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