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Elimination of bromine from 2-bromobutan...

Elimination of bromine from 2-bromobutane results in the formation of
(i)equimolar mixture of 1 and 2-butane
(ii)predominantly2-butene
(iii)predominantly 1-butene
(iv)predominantly 2-butyne.

A

equimolar mixture of 1 and 2 butene

B

predominantly 2-butene

C

predominantly 1-butene

D

predominantly 2-butyne

Text Solution

Verified by Experts

The correct Answer is:
B

`CH_3underset("2-Bromobutane")(CH_2overset(Br)overset(|)(CH)CH_3)overset(KOH(alc.))tounderset("2-Butene(80%)")(CH_3CH=CHCH_3)underset("1-Butene(20%)")(CH_3CH_2CH=CH_2)`
In elimination reaction of alkyl halide major product is obtained according to Sayzeff's rule, which states that when two alkenes may be formed, the alkene which is most substituted one predominates.
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