An alkene `CH_(3)CH = CH_(2)` is treated with `B_(2)H_(6)` in presence of `H_(2)O_(2)` . The final product formed is

Options

A. `CH_(3)CH_(2)CHO`
B. `CH_(3)CH(OH)CH_(3)`
C. `CH_(3)CH_(2)CH_(2) OH`
D. `(CH_(3)CH_(2)CH_(2))_(3)B`

Answer

C

Explanation

`{:(CH_3=CH=CH_2+(CH_3)_2rarrCH_3CH_2CH_2BH_2),(" "darrCH_2CH=CH_2),(" "(CH_3CH_2CH_2)_3"B"overset(CH_3CH=CH_2)larr(CH_3CH_2)_2BH),(" "H_2Odarr3H_2O_2//OH^_),(" "3CH_3CH_2CH_2OH+B(OH)_3):}`