Tertiary butyl alcohol can be prepared by the reaction of

Options

A. acetadehyde and ethyl magnesium iodide
B. acetone and methyl magnesium iodide
C. formaldehyde and propyl magnesium iodide
D. butanone and methyl magnesium iodide.

Explanation

To prepare tertiary butyl alcohol (2-methylpropan-2-ol), we can react acetone (which is a ketone) with a Grignard reagent. Here’s a step-by-step breakdown of the process:

### Step 1: Identify the Reactants
We need to identify the reactants that can produce tertiary butyl alcohol. The key reactant here is acetone (CH₃COCH₃), which is a ketone.

### Step 2: Choose the Grignard Reagent
The Grignard reagent we will use is methyl magnesium iodide (CH₃MgI). This reagent has a methyl group that will act as a nucleophile.

### Step 3: Nucleophilic Addition Reaction
When we react acetone with methyl magnesium iodide, the nucleophilic methyl group (CH₃⁻) from the Grignard reagent attacks the carbonyl carbon of acetone. This leads to the following reaction:

1. The nucleophile (CH₃⁻) attacks the carbonyl carbon (C=O) of acetone.
2. The double bond between carbon and oxygen breaks, leading to a negatively charged oxygen (alkoxide ion).

### Step 4: Formation of the Alkoxide Intermediate
The reaction can be summarized as follows:
- Acetone (CH₃COCH₃) + Methyl magnesium iodide (CH₃MgI) → Alkoxide intermediate (CH₃C(OH)(CH₃)CH₃)

### Step 5: Hydrolysis
The alkoxide intermediate is then subjected to hydrolysis (usually by adding water or an acid), which converts the alkoxide into the corresponding alcohol:

- Alkoxide + H₂O → Tertiary butyl alcohol (2-methylpropan-2-ol) + Mg(OH)I

### Final Product
The final product of this reaction is tertiary butyl alcohol (C₄H₁₀O), which has the structure (CH₃)₃COH.

### Conclusion
Thus, tertiary butyl alcohol can be prepared by the reaction of acetone with methyl magnesium iodide.

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