Total number of atoms present in 34 g of `NH_3` is

Options

A. `4xx10^23`
B. `4.8xx10^21`
C. `2xx10^23`
D. `48xx10^23`

Answer

D

Explanation

No. of moles of 34g of `NH_3=34/17=2`
No. of molecules `=2xx6.023xx10^23`
No. of atoms in one molecules of `NH_3`=4
No. of atoms in `2xx6.023xx10^23 " molecules of NH_3`
`=4xx2xx6.023xx10^23=48.18xx10^23`