If 40g of `CaCO_3` is treated with 40g of HCl, which of the reactants will acts as limiting reagent?

Options

A. `CaCO_3`
B. HCl
C. Both (a) and (b)
D. None of these

Answer

A

Explanation

`underset("1 mole" (100g))(CaCO_3)+underset("2 moles" (73g))(2HCl) to CaCl_2+H_2O+CO_2`
100g of `CaCO_3` reacts with 73g of HCl
40g of `CaCO_3 " will reacts with " 73/100xx40=29.2g` of HCl
Since `CaCO_3` is completely consumed and some amount (40-29.2=10.8g) of HCl remains unreacted and hence, `CaCO_3` is limiting reagent.