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At NTP, 1L of O2 reacts with 3L of carbo...

At NTP, 1L of `O_2` reacts with 3L of carbon monoxide. What will be the volume of CO and `CO_2` after the reaction?

A

1L `CO_2`, 1L CO

B

2L `CO_2`, 2L CO

C

1L `CO_2`, 2L CO

D

2L `CO_2`, 1L CO

Text Solution

Verified by Experts

`underset(2 Vol )(2CO)+underset(1vol)(O_2) to underset(2vol)(2CO_2)`
1 vol of `CO_2` reacts with 2 vol of CO
1 L of `CO_2` reacts with 2 L of CO
CO left after reaction = 3-2=1L
1L of `O_2` produces 2L of `CO_2`
Hence, after the reaction, CO =1L, `CO_2=2L`
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