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Chlorine gas is prepared by reaction of ...

Chlorine gas is prepared by reaction of `H_2SO_4` with `MnO_2` and NaCl. What volume of `Cl_2` will be produced at STP if 50 g of NaCl is taken in the reaction ?

A

1.915 L

B

22.4 L

C

11.2 L

D

9.57 L

Text Solution

Verified by Experts

`2NaCl+MnO_2 + 3H_2SO_4 to 2NaHSO_4 + MnSO_4 + Cl_2 + 2H_2O`
`{:("2 moles","1 mole"),("(2 x 58.5 = 117 g )", "22.4 L (STP)"):}`
117g of NaCl `-= 22.4L " of " Cl_2`
50g of NaCl`-=(22.4)/(117)xx50=9.57 L " of " Cl_2` at STP
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