HCl is produced in the stomach which can be neutralised by `Mg(OH)_2` in the form of milk of magnesia. How much `Mg(OH)_2` is required to neutralise one mole of stomach acid?

Options

A. 29.16 g
B. 34.3 g
C. 58.33 g
D. 68.66g

Explanation

`Mg(OH)_2+2HCl to MgCl_2 + 2H_2O`
No. of moles of `Mg(OH)_2` required for 2 moles of HCl = 1
No. of moles of `Mg(OH)_2` required for 1 mole of HCl = 0.5
mass of 0.5 mol of `Mg(OH)_2=58.33xx0.5=29.16g`