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Hydrogen gas is prepared in the laborato...

Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc, Following reaction takes place
`Zn+2HClrarrZnCl_(2)+H_(2)`
Calculate the voluem of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of Zn=65 .3u

A

10.03 L

B

11.35 L

C

11.57 L

D

9.53 L

Text Solution

Verified by Experts

`underset(65.3g)(Zn) + 2HCl to ZnCl_2 + underset (22.7L)(H_2)`
According to the equation,
65.3g of Zn liberates = 22.7 L of `H_2`
32.65g of Zn will liberate `=(22.7)/(65.3)xx32.65=11.35L`
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