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A compound on analysis was found to cont...

A compound on analysis was found to contain the following composition :
`Na=14.31%,S=9.97%,O=69.50 %and H=6.22 %`
Calculate the molecular formula of the compound assuming that the whole of hydrogen in the compound is present as water of crystallisation. Molecular mass of the compound is 322.

A

`Na_2SO_4`

B

`Na_2SO_(4) . 10H_2O`

C

`Na_2SH_10O_12`

D

`Na_2SO_(4) . 7H_2O`

Text Solution

Verified by Experts


Empirical formula mass = 46 + 32 + 20 + 224 = 322
`n= (" molecular mass " )/("empirical formula mass")=322/322=1`
Hence, molecules formula `=Na_2SH_20O_14`
Since, all the hydrogen is in the form of water, thus there are `10H_2O` molecules. Hence, the molecular formula is `Na_2SO_(4).10H_2O`
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