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The density of 3 molal solution of NaOH ...

The density of 3 molal solution of NaOH is 1.110g `mL^(-1)`. Calculate the molarity of the solution.

A

2.69 M

B

2.97 M

C

4.57 M

D

6.70 M

Text Solution

Verified by Experts

The correct Answer is:
B
Molality of solution = 3m
Density of solution = 1.110g `mL^(-1)`
3m = no. of moles of NaOH per Kg of solvent =3
Mass of solution = 1000 ( solvent) + 3 x 40 ( solute)
=1000 + 120 = 1120 g
Volume of solution `=1120/(1.110)=1009.00mL`
`M=(n)/(V("in L"))=(3)/(1009.00)xx1000=2.97M`
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