How many number of electrons are present in a particle which carries a charge of `5.5xx10^(-16)C?`

Options

A. 3432
B. 1560
C. 8240
D. 2432

Explanation

To find the number of electrons present in a particle that carries a charge of \(5.5 \times 10^{-16} \, \text{C}\), we can follow these steps:

### Step 1: Understand the charge of one electron
The charge of a single electron is approximately \(1.6 \times 10^{-19} \, \text{C}\).

### Step 2: Use the formula to find the number of electrons
To find the number of electrons (\(n\)) that corresponds to a total charge (\(Q\)), we can use the formula:
\[ n = \frac{Q}{e} \]
where \(Q\) is the total charge and \(e\) is the charge of one electron.

### Step 3: Substitute the values into the formula
Substituting the values we have:
\[ n = \frac{5.5 \times 10^{-16} \, \text{C}}{1.6 \times 10^{-19} \, \text{C}} \]

### Step 4: Calculate the number of electrons
Now, perform the division:
\[ n = \frac{5.5}{1.6} \times \frac{10^{-16}}{10^{-19}} = \frac{5.5}{1.6} \times 10^{3} \]
Calculating \( \frac{5.5}{1.6} \):
\[ \frac{5.5}{1.6} \approx 3.4375 \]
Thus,
\[ n \approx 3.4375 \times 10^{3} \approx 3437.5 \]

Since the number of electrons must be a whole number, we round it to the nearest whole number:
\[ n \approx 3438 \]

### Final Answer:
The number of electrons present in the particle is approximately **3438**.

---