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The energy of a photon is given as 3.03x...

The energy of a photon is given as `3.03xx10^(-19)J`. The wavelength of the photon is

A

6.56 nm

B

65.6 nm

C

0.656 nm

D

656 nm

Text Solution

Verified by Experts

The correct Answer is:
D
`E=(hc)/lamdaorlamda=(hc)/E
lamda=(6.626xx10^(-34)Jsxx3xx10^(8)ms^(-1))/(3.03xx10^(-19)J)
6.56xx10^(-7)m or 656nm`
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