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Compare the energies of two radiations E...

Compare the energies of two radiations `E_(1)` with wavelength 800 nm and `E_(2)` with wavelength 400 nm.

A

`E_(1)=2E_(2)`

B

`E_(1)=E_(2)`

C

`E_(2)=2E_(1)`

D

`E_(2)=-1/2E_(1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(1)=(hc)/lambda_(1),E_(2)=(hc)/lambda_(2)
(E_(1))/(E_(2))=(hc)/lambda_(1)xx(lambda_(2))/(hc)or(E_(1))/(E_(2))=(lambda_(2))/(lambda_(1))=400/800
(E_(1))/(E_(2))=1/2 or E_(2)=2E_(1)`
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