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The energy difference between ground sta...

The energy difference between ground state of an atom and its excited state is `3xx10^(-19)J`. What is the wavelength of photom required for this radiation ?

A

`6.6xx10^(-34)`m

B

`3xx10^(-8)`m

C

`1.8xx10^(-7)`m

D

`6.6xx10^(-7)`m

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaE=(hc)/lambda
lambda=(6.6xx10^(-34)Jsxx3xx10^(8)ms^(-1))/(3xx10^(-19)J)=6.6xx10^(-7)m`
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