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A 100 watt bulb emits monochromatic ligh...

A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb.

A

`3xx10^(20)s^(-1)`

B

`2xx10^(-20)s^(-1)`

C

`2xx10^(20)s^(-1)`

D

`1xx10^(-20)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Power of the bulb = 100 watt = `100Js^(-1)`
Energy of one photon E = hv = `hc//lambda
= (6.626xx10^(-34)Jsxx3xx10^(8)ms^(-1))/(400xx10^(-9)m)=4.969xx10^(-19)J`
Number of photons emitted
= `(100Js^(-1))/(4.969xx10^(-19)J)=2.012xx10^(20)s^(-1)`
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