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If uncertainty principle is applied to a...

If uncertainty principle is applied to an object of mass 1 miligram, the product of uncertainly in velocity and position will be:

A

`0.2xx10^(-4)m^(2)s^(-1)`

B

`0.52xx10^(6)m^(2)s^(-1)`

C

`0.52xx10^(-28)m^(2)s^(-1)`

D

`2xx10^(-34)m^(2)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Deltav.Deltax=h/(4pim)=(6.626xx10^(-34)Js)/(4xx3.14xx10^(-6)kg)
= 0.52xx10^(-28)m^(2)s^(-1)" "(1mg=10^(-6)kg)`
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