Home
Class 11
CHEMISTRY
On hybridisation of one s and three p-or...

On hybridisation of one s and three p-orbitals, we get

A

four orbitals with tetrahedral orientation

B

three orbitals with trigonal orientation

C

two orbitals with linear orientation

D

two orbitals with perpendicular orientation.

Text Solution

Verified by Experts

The correct Answer is:
A

Four `sp^(3)` hybrid orbitals are formed when one s and three p - orbitals hybridise .
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING & MOLECULAR STRUCTURE

    NCERT FINGERTIPS|Exercise Molecular Orbital Theory|18 Videos

  • CHEMICAL BONDING & MOLECULAR STRUCTURE

    NCERT FINGERTIPS|Exercise Bonding In Some Homonuclear Diatomic Molecules|4 Videos

  • CHEMICAL BONDING & MOLECULAR STRUCTURE

    NCERT FINGERTIPS|Exercise Valence Bond Theory|7 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

One hybridization of one s and one p orbital we get

" Inter mixing of one s-orbital,three p-orbitals and one d-orbital to give "5sp^(3)d" hybrid orbitals is called "

In order to explain the characteristic geometrical shapes of polyatomic molecules, Pauling introduced the concept of hybridisation. The orbitals undergoing hybridisation should have nearly same energy. There are various types of hybridisations involving s, p and d - type of orbitals. The type of hybridisation gives the characteristic shape of the molecular or ion. Which molecule does not have the same type of hybridisation as P has in PF_(5) ?

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :