Which of the following pairs have identical bond order?

Options

A. `F_(2) and O_(2)^(2-)`
B. `N_(2) and CO_(2)`
C. `O_(2) and O_(2)^(-)`
D. `N_(2) and N_(2)^(+)`

Answer

A

Explanation

`F_(2) and O_(2)^(2-)` are isoelectronic .
`F_(2) : (sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(sigma2p_(z)^(2)) (sigma2p_(z)^(2)=pi2p_(y)^(2))(pi^(**)2p_(x)^(2) = pi ^(**)2p_(y)^(2))`
B.O.` = 1/2 xx (10 - 8) = 1`
`O_(2)^(2-) : (sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(sigma2p_(z)^(2))(pi 2p_(x)^(2) = pi 2p_(y)^(2))(pi^(**)2p_(x)^(2) = pi^(**)2p_(y)^(2))`
B.O. ` = (10-8)/2 = 1`