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34.05 mL of phosphorus vapours weighs 0....

`34.05 mL` of phosphorus vapours weighs `0.0625 g` at `546^(@)C` and `0.1` bar pressure. What is the molar mass of phossphorus ?

A

`124 . 77 g mol^(-1)`

B

`1247 . 74 g mol ^(-1)`

C

`12 . 47 g mol^(-1)`

D

`30 g mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`M=(mRT)/(PV)=(0.0625xx0.083xx819)/(0.1xx(34.05//1000))`
`=1247.74 g mol^(-1)`
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