In a flask of volume V litres, 0.2 mol of oxygen 0.4 mol of nitrogen, 0.1 mole of `NH_(3)` and 0.3 mol of He are enclosed at `27^(@)C`. If the total pressure exerted by these non reacting gases is one atmosphere, the partial pressure exerted by nitrogen is

Options

A. 0.1 atmosphere
B. 0.2 atmosphere
C. 0.3 atmosphere
D. 0.4 atmosphere

Answer

D

Explanation

`P_(N_(2))=(0.4)/(0.2+0.4+0.1+0.3)xx1=0.4` atm
(`because` Partial pressure = mole fraction `xx` total pressure)