The pressure of a mixture of equal weight of two gases of mol wt. 4 and 40, is 1.1 atm. The partial pressure of the lighter gas in this mixture is

Options

A. 1 atm
B. 0.1 atm
C. 0.15 atm
D. 0.5 atm

Answer

A

Explanation

Let w g of each gas is taken.
Mole fraction of `X=((w)/(4))/((w)/(4)+(w)/(40))=(10)/(11)`
Partial pressure of `X = P_("total")xx` Mole fraction
`= 1.1xx(10)/(11)=1` atm