A bubble of air is underwater at temperature `15^(@)C` and the pressure `1.5` bar. If the bubble rises to the surface where the temperature is `25^(@)C` and the pressure is `1.0` bar, what will happen to the volume of the bubble?

Options

A. Volume will become greater by a factor of 1.55.
B. Volume will become greater by a factor of 1.1.
C. Volume will become smaller by a factor of 0.70.
D. Volume will become greater by a factor of 2.5.

Answer

A

Explanation

We know that from ideal equation,
`V prop (T)/(P)`
Given `T_(1)=15+273=288K, P_(1)=1.5` bar
`T_(2)=25+273=298K, P_(2)=1` bar
`V_(1)prop (288)/(1.5)i.e., V_(1) prop 192 , V_(2) prop (298)/(1)`
`(V_(2))/(V_(1))=(298)/(192)=1.55`