Home
Class 11
CHEMISTRY
The rms speed of N(2) molecules in a gas...

The `rms` speed of `N_(2)` molecules in a gas in `u`. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atom, the `rms` speed becomes

A

u / 2

B

2u

C

4u

D

12u

Text Solution

Verified by Experts

The correct Answer is:
B
`u_(N_(2))=sqrt((3RT)/(M))`
Mass of nitrogen atom `=("Mass of nitrogen molecule")/(2)=(M)/(2)`
`u_(N_(2))=sqrt((3R(2T))/(M//2))=2sqrt((3RT)/(M))=2u_(N_(2))`
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER

    NCERT FINGERTIPS|Exercise Kinetic Molecular Theory Of Gases|4 Videos

  • STATES OF MATTER

    NCERT FINGERTIPS|Exercise Behaviour Of Real Gases|15 Videos

  • STATES OF MATTER

    NCERT FINGERTIPS|Exercise Ideal Gas Equation|33 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NCERT FINGERTIPS|Exercise Assertion And Reason|10 Videos

  • STRUCTURE OF ATOM

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

The rms speed of pzygen molecules in a gas in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become

The rms speed of oxygen molecules in a gas is Delta. If the temperature is doubled and the O_(2) molecule dissociated into oxygen atoms, the rms speed will become

The avergae speed of nitrogen molecules in a gas is v . If the temperature is doubled and the N_(2) molecule dissociate into nitrogen atoms, then the average speed will be