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For an isothermal reversible expansion p...

For an isothermal reversible expansion process, the value of q can be calculated by the expressin

A

`q=2.30 n RT log. (V_(2))/(V_(1))`

B

`q=-2.303nRT log.(V_(2))/(V_(1))`

C

`q=-2.303 nRT log. (V_(1))/(V_(2))`

D

`q=-P_("exp")nRT log.(V_(1))/(V_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`q=-W=2.303nRT log(V_(2))/(V_(1))`
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