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Reaction of methanol with dioxygen was c...

Reaction of methanol with dioxygen was carried out and `DeltaU` was found to be `-726"kJ mol"^(-1)` at 298 K. The enthalpy change for the reaction will be
`CH_(3)OH_((l))+(3)/(2)O_(2(g)) rarr CO_(2(g))+2H_(2)O_((l)) , DeltaH=-726"kJ mol"^(-1)`

A

`-"741.5 kJ mol"^(-1)`

B

`-"727 kJ mol"^(-1)`

C

`+"741.5 kJ mol"^(-1)`

D

`+"727.2 kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Deltan_(g)=1-(3)/(2)=-(1)/(2)`
`DeltaH=DeltaU+Deltan_(g)RT`
`=-726xx"1000 J mol"^(-1)(-(1)/(2)xx"8.314 J K"^(-1)"mol"^(-1)xx"298 K")`
`=-"727238.78 J mol"^(-1)=-"727 kJ mol"^(-1)`
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