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The value of K(c) for the following equi...

The value of `K_(c)` for the following equilibrium is
`CaCO_(3(s))hArrCaO_((s))+CO_(2(g))`.
Given `K_(p)=167` bar at 1073 K.

A

`1.896" mol L"^(-1)`

B

`4.38xx10^(-4)" mol L"^(-1)`

C

`6.3xx10^(-4)" mol L"^(-1)`

D

`6.626" mol L"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(p)=K_(c)(RT)^(Deltan)," "Deltan=1`
`K_(p)=167" bar"`,
`K_(c)=(167" bar")/(0.0821"L bar K"^(-1)"mol"^(-1)xx1073K)=1.896" mol L"^(-1)`
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