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NH(4)COONH(4)(s) hArr 2NH(3)(g)+CO(2)(g)...

`NH_(4)COONH_(4)(s) hArr 2NH_(3)(g)+CO_(2)(g)`. If equilibrium pressure is `3` atm for the above reaction, `K_(p)` will be

A

27

B

4

C

3

D

9

Text Solution

Verified by Experts

The correct Answer is:
B
`NH_(4)COONH_(2(g))hArrunderset(2p)(2NH_(3(g)))+underset(p)(CO_(2(g)))`
When volume and temperature are constant the number of moles of a gas is proportional to its partial pressure.
So, `2p+p=3`
`3p=3," ":." "p=1" atm"`
`K_(p)=(2p)^(2)xxp=4p^(3)=4xx(1)^(3)=4" atm"^(3)`
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