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The expression for equilibrium constant,...

The expression for equilibrium constant, `K_(c)` for the following reaction is
`2Cu(NO_(3))_(2(s))hArr2CuO_((s))+4NO_(2(g))+O_(2(g))`

A

`K_(c)=([CuO_((s))]^(2)[NO_(2(g))]^(4)[O_(2(g))])/([Cu(NO_(3))_(2(s))]^(2))`

B

`K_(c)=([NO_(2(g))]^(4)[O_(2(g))])/([Cu(NO_(3))_(2(g))]^(2))`

C

`K_(c)=[NO_(2(g))]^(4)[O_(2(g))]`

D

`K_(c)=([CuO_((s))]^(2))/([Cu(NO_(3))_(2(g))]^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`2Cu(NO_(3))_(2(s))hArr2CuO_((s))+4NO_(2(g))+O_(2(g))`
Since conc. of solids is taken as 1, the expression for `K_(c)` becomes
`K_(c)=[NO_(2g)]^(4)[O_(2(g))]`
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