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The expression for equilibrium constant,...

The expression for equilibrium constant, `K_(c)` for the following reaction is
`Fe_((aq))^(3+)+3OH_((aq))^(-)hArrFe(OH)_(3(s))`

A

`K_(c)=([Fe(OH)_(3)])/([Fe^(3+)][OH^(-)]^(3))`

B

`K_(c)=([Fe(OH)_(3)])/([Fe^(3+)][OH^(-)])`

C

`K_(c)=(1)/([Fe^(3+)][OH^(-)]^(3))`

D

`K_(c)=[Fe(OH)_(3)]`

Text Solution

Verified by Experts

The correct Answer is:
C

For `Fe_((aq))^(3+)+3OH_((aq))^(-)hArrFe(OH)_(3(s))`
`K_(c)=(1)/([Fe^(3+)][OH^(-)]^(3))`
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